Because I am too busy blowing out candles today, my tall, dark, handsome, and incredibly geeky fabulous boyfriend took it upon himself to "guest blog" for me. Here is the product, wherein he demonstrates how I am in the square prime of my life. Enjoy!
* * *
While lying in bed with my sexy girlfriend on the morning of her birthday, I noted that her age is now the product of a prime number and a square. For a review for those who haven't thought about math since Mr. Johnson kicked you out of Analytical Geometry for being drunk (oh wait, that was me), a prime is a number only divisible by one and itself (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31 ...), and a square is the product of a number times itself (4, 9, 16, 25, 36 ...)
Of course, knowing her own age, she was able to determine the numbers in question. Let's call them p1 and s1. Without having figured out the answer yet, I postulated, "When is the next time that will happen?" Giving up all too quickly to befit her geek creds, she said she didn't know. When I told her it would happen next year, she thought about it for a few seconds and said, "You mean p2 and s2?"
Now p2 is a prime, and s2 is a square, but the product of them is not her age next year. The sum of them is! "Wow!" I thought, that's really interesting, next year is her age not only the product of a square and a prime, but also the sum! (So there is also p3 and s3, which were the ones I thought of that work if you multiply them.)
So after a reasonable amount of birthday canoodling, I get up to take a shower. And of course the brain is still cranking away with squares and primes, when I realize that next year, there will be another Square Prime set where the sum will be her age, AND this year there is a set where the sum is her age! When will the madness end?
So for those who always thought the hardest part of the story problems was putting them into equations, I'll do that part for you:
p1 * s1 = Age this year
p2 + s2 = Age next year
p3 * s3 = Age next year
p4 + s4 = Age next year
p5 + s5 = Age this year
One of the really neat things about this is that it works for you too! That is, when you are Jodi's age, all of the figures will still work. But it is unlikely that any of us will work our figures the way Jodi does, nor have a figure that works so well.
Please have your answers submitted by the beginning of class next Friday.
Um, Jodi? No. It's not just you. It is DEFINITELY getting HOTTT in here.
I'm seeing Math in a whole new light!
Offered by: jamied on October 27, 2007 1:06 AMGrrrr - OH - FUCK YOU ALL AND YOUR NEW MATH CANOODLING!!!
I'd settle for a "can" - WAIT - I mean a noodle.
Ahem. Pardon. And I hope that the last hour (EST) of your birthday, Jo-delight, is a pure orgamsmic delight.
Amen.
Offered by: Kate on October 26, 2007 11:07 PMOkay, I *officially* approve of your main squeeze! Oh, and happy birthday!!!!!
Offered by: Vendela on October 26, 2007 9:11 PMToken -
Now I have a 1/10th understanding of why our jodes is so smitten - your unwavering desire to make others as happy as they can be, on top, on the bottom, or split between extremes.
The other 9/10's I wouldn't even want to speculum about.
Offered by: Ds on October 26, 2007 7:39 PMds, I assume you meant
((j+j)/ds) + d = xxx
Otherwise you just have jamied on top of you, which of course would be enough for most men, but it sounds as if you had something more exotic in mind.
And I don't have a video camera, but I would buy one in a heartbeat.
I would also think that your fraction would be better if the reciprocal were used so you could get that "goezinto" effect working for you. Just a suggestion.
Offered by: Token Fella on October 26, 2007 5:14 PMcrap. friday typing.
Jodi, put an edit comments feature into this blog.... ;)
Offered by: Ds on October 26, 2007 4:46 PMHm... the mind boggles... not to be confused with Boggle! in which the mind lines up random letters in odd ways to form words that no one every uses but which seem to be a part of our lexicon regardless. But I digree, per usual....
What I REALLY want to know is...
In '(j + j/ds) + d = xxx', if jodi and jamie are on top of me, is it token left on the outside holding the videocamera?
ok, fair enough on the 1 as prime and square. In fact, if you include 1 both sets, then you could be 5, 20 ,40, 45, or 80. If you don't include 1, then 5 isn't possible. Note that I'm actually not that good at puzzles, but I know how to program a computer, and I'm easily distracted on Fridays. (also note that several of the equations have multiple solutions. If you are 40, I'll bet you weren't thinking if 121-81!)
and ds, don't you go worrying your pretty little head over our pp. Tonight we will be doing plenty of
Division, like j/d (you know, how many times does d go into j),
Fractions d/j, j/d (d over j and j over d)
Logarithms (that one just sounds dirty)
Surface Integrals (I'll let your minds run wild with that one.)
p1(1) + s1(4) = age(5)
s2(9) - s3(4) = age(5)
p2(2) + p3(3) = age(5)
s4(1) + s5(4) = age(5)
5 works!
p1(11) + s1(9) = age(20)
p1(19) + s1(1) = age(20)
s2(36) - s3(16) = age(20)
p2(1) + p3(19) = age(20)
p2(3) + p3(17) = age(20)
p2(7) + p3(13) = age(20)
s4(4) + s5(16) = age(20)
20 works!
p1(31) + s1(9) = age(40)
s2(49) - s3(9) = age(40)
s2(121) - s3(81) = age(40)
p2(3) + p3(37) = age(40)
p2(11) + p3(29) = age(40)
p2(17) + p3(23) = age(40)
s4(4) + s5(36) = age(40)
40 works!
p1(29) + s1(16) = age(45)
p1(41) + s1(4) = age(45)
s2(49) - s3(4) = age(45)
s2(81) - s3(36) = age(45)
p2(2) + p3(43) = age(45)
s4(9) + s5(36) = age(45)
45 works!
p1(31) + s1(49) = age(80)
p1(71) + s1(9) = age(80)
p1(79) + s1(1) = age(80)
s2(81) - s3(1) = age(80)
s2(144) - s3(64) = age(80)
p2(1) + p3(79) = age(80)
p2(7) + p3(73) = age(80)
p2(13) + p3(67) = age(80)
p2(19) + p3(61) = age(80)
p2(37) + p3(43) = age(80)
s4(16) + s5(64) = age(80)
80 works!
Hmmm. No one bothered to do MY Birthday math. And just because I don't have a hunky bedfellow (Kitten Children are DEFINITELY not hunky - sometimes sweet and cuddly, sometimes they BITE) to guest blog that doesn't mean that the birthday girl shouldn't ALWAYS be obeyed!
Well, Ms. Jodi The Almost New Yorker Cartoonist, I don't know if I'll get to overly-flashy greetings for you on my blog as I did last year, but I do not love you any less. Happiest of natal days (or daze?) to you!
Offered by: Kate on October 26, 2007 4:34 PMOK, AM I THE ONLY ONE WHO IS WONDERING WHAT I CONSIDERED TO BE THE OBVIOUS?!?!?!?!?
If (a) tokenfella and (b) jodi were (c) lying in her birthdaybed 'canoodling,' one would expect the sum of a + b + c to equal pp.
Now obviously if token is so taken with his integerial endeavours that he can't get up his equation whilst 'canoodling,' his pp won't be getting any attention either.
So it is my suggestion that instead of worrying about primes and squares, the geeksquad put away their sliderules, skip the p1's, p2's and p3's and gets back to the business at hand (so to speak.) The pp's.
After all, it is jodi's birthday and I know she's hoping that token's package is more than a math quiz.
Offered by: Ds on October 26, 2007 4:02 PMIs it just me, or is it extremely hottt in here?
Offered by: Jodi on October 26, 2007 3:22 PMum, actually it was 44 on each "side". Already done. check.
and Mrs. Z, you might want to change your phrasing to encourage my generosity. Accordiing to your plan, it would be in my interest to NOT provide more presents. But alas, I will.
Offered by: Token Fella on October 26, 2007 3:13 PMWhy start the squares at 2? One (also a number) squared is 1. In fact, zero squared is zero. What about i-squared, which is -1? And radical 2 squared is 2. And so on. All of these are numbers. Now, if you narrow it to positive integers, you still have to include 1 in the list of squares. Ok, I know, you meant positive integers greater than 1.
I myself am at an age that is the sum of a prime and a square (p1 + s1), a square minus a square (s2 - s3), a prime plus a prime (p2 + p3), and a square plus a square (s4 + s5) (all positive integers greater than one, with some repeats). And none of that makes me feel any better about it.
Offered by: tim on October 26, 2007 3:11 PMMy brain hurts, but like the birthday girl, I loooooove pain.
Token, prepare yourself for pain while vainly attempting to inflict it 44 times on Jodi's rock hard birthday booty. You might just break your hand in your conquest for a whimper.
Offered by: jamied on October 26, 2007 2:27 PMOops, I did this without the benefit of the big JPEG giving your current age. Makes it a little too easy, don'tcha think? Anyway:
p1 * s1 = 11 * 4 = 44 = Age this year
p2 + s2 = 29 + 16 = 45 = Age next year
p3 * s3 = 5 * 9 = 45 = Age next year
p4 + s4 = 41 + 4 = 45 = Age next year
p5 + s5 = 19 + 25 = 44 = Age this year
And of course the next 5 times the product will happen:
48 (16 * 3),
49 (technically: 1 * 49)
50 (25 * 2),
52 (4 * 13)
63 (9 * 7)
Interesting that last bit ... four out of five, and then a big gap. Prime numbers are fascinating.
You guys are such geeks!
Offered by: Kerry on October 26, 2007 2:24 PMWell, you lost Mrs. Z halfway through the first paragraph with your boring mathematical babble. And while you are clearly a big giant dork, Jodi is lucky to have a beau who cares enough to guest blog. But if this was Jodi's only present, you're screwed.
Offered by: Mrs. Z on October 26, 2007 2:16 PM
